Question

编写一个Java程序计算1!+2!+.....+10!的和

Answer 1

import java.math.*;
import java.io.*;
class fac
{
public static void main(String args[])
{ BigInteger n1=new BigInteger("0"),
n2=new BigInteger("1"),
result=null;
for(int i=1;i!=11;i++)
{
for(int j=1;j!=i+1;j++)
n2=n2.multiply(new BigInteger(String.valueOf(j)));
n1=n1.add(n2);n2=new BigInteger("1");
}
System.out.println(n1.toString());
}
}

Answer 2

------------------循环算颂此法-------------------------
public class text {
public static void main(String args[]) {
text t = new text();
System.out.print(t.sum());
}
public int sum(){
int a = 0;
for(int i=1;i<磨芦=10;i++){
int b = 1;
for (int j = 1; j <=i; j++) {
b = b*j;
}
a=a+b;
}
return a;
}
}
----------------递归算------------------------------------------
import java.io.*;
public class jiecheng
{
public static long fac(int n)
{long res=1;
for(int k=2;k<=n;k++)
res*=k;
return res;}
public static void main(String args[]) throws IOException
{long sum=0;int i=1,n=20;
for(i=1;i<=n;i++)
sum+=fac(i);
System.out.println("前"+n+"项阶乘的和为瞎樱带："+sum);
}
}