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(x+2y-3)(x-2y+3)-(x-2y-3)²
展开全部
原式=[x+(2y-3)][x-(2y-3)]-[(x-2y)-3]²
=x²-(2y-3)²-(x-2y)²+6(x-2y)-9
=x²-4y²+12x-9-x²+4xy-4y²+6x-12y-9
=-8y²+4xy+18x-12y-18
=x²-(2y-3)²-(x-2y)²+6(x-2y)-9
=x²-4y²+12x-9-x²+4xy-4y²+6x-12y-9
=-8y²+4xy+18x-12y-18
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