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原式=sin（x+π/3）+√3cos（x+π/3）+2sin（x-π/3）
=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)
=2sin(x+π/3+π/6)+2sin(x-π/3)
=2[sin(x+π/2)+sin(x-π/3)]
=2(cosx+√3/2sinx-1/2cosx)
=2(√3/2sinx+1/2cosx)
=2sin(x+π/6)
=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)
=2sin(x+π/3+π/6)+2sin(x-π/3)
=2[sin(x+π/2)+sin(x-π/3)]
=2(cosx+√3/2sinx-1/2cosx)
=2(√3/2sinx+1/2cosx)
=2sin(x+π/6)
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