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急,求解函数!
2个回答
展开全部
f(x)=根号下x
f(x2-2x+1)=√(x-1)^2
0.5=√0.25
f(x2-2x+1)<0.5
即
(x-1)^2<0.25
(x-1-0.5)(x-1+0.5)<0
(x-1.5)(x-0.5)<0
0.5<x<1.5
f(x2-2x+1)=√(x-1)^2
0.5=√0.25
f(x2-2x+1)<0.5
即
(x-1)^2<0.25
(x-1-0.5)(x-1+0.5)<0
(x-1.5)(x-0.5)<0
0.5<x<1.5
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