Question

帮忙算一下

已知F(H)=[(H²+d²)g]/[2(H-h)] （其中d、g、h为常数）求F'(H)

Answer 1

F'(H)=g/2*(2H^2-2Hh-H^2-d^2)/(H-h)^2
=g/2*(H^2-2Hh-d^2)/(H-h)^2
=g/2*[(H-h)^2-(h^2+d^2)/(H-h)^2
=g/轮歼2-g(h^2+d^2)/亮桐物敬液[2(H-h)^2]