Question

求一个c语言程序答案

输入一个表达式，类似于“xopy”，其中x、y是实数，op是加、减、乘、除运算符，然后求出该表达式的值

Answer 1

#include<stdio.h>
void main()
{
int num1,num2;
char fuhao;
printf("请输入两个数");
scanf("%d%d",&num1,num2);
printf("请输入运算符（+-*/）");
scanf("%c",&fuhao);
switch(fuhao)
{
case '+':printf("%d+%d=%d",num1,num2,num1+num2);break;后面依此类推
}
}

Answer 2

#include<stdio.h>int main()
{
double a,b,e;
char c;
scanf("%lf%c%lf",&a,&c,&b);
if(c=='+') e=a+b;
if(c=='-') e=a-b;
if(c=='*') e=a*b;
if(c=='\/') e=a/b;
printf("%f %c %f = %f \n",a,c,b,e);
return 0;
}

Answer 3

#include"stdio.h"
void main()
{
long x1(0),x2(0);
char x3;
printf("请输入算式:");
scanf("%ld",&x1);
scanf("%c %ld",&x3,&x2);
switch(x3)
{
case '+':

printf("%d",x1+x2);break;
case '-':

printf("%d",x1-x2);break;
case '*':

printf("%d",x1*x2);break;
case '/':

printf("%f",(float)(x1*100)/x2/100);break;
default:printf("输入错误！");
}
printf("\n");
}

Answer 4

求我，姐姐就跟你讲，要不要啊，呵呵