Question

化简(a^2/a-3+9/3-a)÷(a+3)/a

最后是除以a分之a+3

Answer 1

[A^2/(A-3)+9/(3-A)]÷[(A+3)/A]=[A^2/(A-3)-9/(A-3)]X[A/(A-3)]=[(A^2-9)/(A-3)]X[A/(A-3)]=[(A+3)(A-3)/(A-3)]X[A/(A-3)]=A(A+3)/(A-3)

Answer 2

化简（a�0�5/a-3+9/a-3)/(a+3/a)的结果为
{(a�0�5+9)/a-6}(a+3/a)=(a�0�5+9)-3(a�0�5+9)/a�0�5-6a-18/a
={(a�0�5+9)a�0�5-3(a�0�5+9)}/a�0�5-(6a�0�5/a�0�5)-18a/a�0�5
=(a^4+9a^2-3a^2-27-6a^2-18a)/a�0�5
=(a^4-18a-27)/a^2

Answer 3

(a^2/a-3+9/3-a)÷(a+3)/a=(a�0�5/a-3-9/a-3)÷a+3/a=(a-3)(a+3)/a-3×a/a+3=a

Answer 4

a