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解(2x-y)^3-(x-y)^3
=[(2x-y)-(x-y)][(2x-y)^2+(2x-y)(x-y)+(x-y)^2]
=(x)[4x^2-4xy+y^2+2x^2-3xy+y^2+x^2-2xy+y^2]
=x(7x^2-9xy+3y^2)
=[(2x-y)-(x-y)][(2x-y)^2+(2x-y)(x-y)+(x-y)^2]
=(x)[4x^2-4xy+y^2+2x^2-3xy+y^2+x^2-2xy+y^2]
=x(7x^2-9xy+3y^2)
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