(1)-22-|-3|(2)15×(?5)÷(?15)×5(3)12-(-18)+(-7)-15(4)(-10)+8×(-2)2-(-4)×(-3
(1)-22-|-3|(2)15×(?5)÷(?15)×5(3)12-(-18)+(-7)-15(4)(-10)+8×(-2)2-(-4)×(-3)(5)(?56+23?...
(1)-22-|-3|(2)15×(?5)÷(?15)×5(3)12-(-18)+(-7)-15(4)(-10)+8×(-2)2-(-4)×(-3)(5)(?56+23?34)÷112(6)(-2)3-22-(-1)2004÷[(13?12)]×6-|5|
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(1)-2
2-|-3|
=-4-3
=-7;
(2)
×(?5)÷(?)×5=1×5×5
=5×5
=25;
(3)12-(-18)+(-7)-15
=12+18-7-15
=30-22
=8;
(4)(-10)+8×(-2)
2-(-4)×(-3)
=-10+8×4-12
=-10+32-12
=10;
(5)(
?+?)÷
=(
?+?)×12
=-
×12+
×12-
×12
=-10+8-9
=-11;
(6)(-2)
3-2
2-(-1)
2004÷[(
?)]×6-|5|
=-8-4-1÷
×6-5
=-8-4-36-5
=-53.
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