Question

数学求导

F(x)=x(x+1)(x+2)…(x+2009)，求函数导函数，要有过程哈，谢谢啦

Answer 1

两边取对数有：lnF(x)=lnx+ln(x+1)+....+ln(x+2009)，则F'(X)/F(x)=[1/x+1/(x+1)+...+1/(x+2009)]，从而就有F'(X)=[1/x+1/(x+1)+...+1/(x+2009)]*F(x)