c#怎么将json转换成xml
2016-09-27 · 知道合伙人数码行家
huanglenzhi
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/// <summary>
/// json字符串转换为Xml对象
/// </summary>
/// <param name="sJson"></param>
/// <returns></returns>
public static XmlDocument Json2Xml(string sJson)
{
//XmlDictionaryReader reader = JsonReaderWriterFactory.CreateJsonReader(Encoding.UTF8.GetBytes(sJson), XmlDictionaryReaderQuotas.Max);
//XmlDocument doc = new XmlDocument();
//doc.Load(reader);
JavaScriptSerializer oSerializer = new JavaScriptSerializer();
Dictionary<string, object> Dic = (Dictionary<string, object>)oSerializer.DeserializeObject(sJson);
XmlDocument doc = new XmlDocument();
XmlDeclaration xmlDec;
xmlDec = doc.CreateXmlDeclaration("1.0", "gb2312", "yes");
doc.InsertBefore(xmlDec, doc.DocumentElement);
XmlElement nRoot = doc.CreateElement("root");
doc.AppendChild(nRoot);
foreach (KeyValuePair<string, object> item in Dic)
{
XmlElement element = doc.CreateElement(item.Key);
KeyValue2Xml(element, item);
nRoot.AppendChild(element);
}
return doc;
}
private static void KeyValue2Xml(XmlElement node, KeyValuePair<string, object> Source)
{
object kValue = Source.Value;
if (kValue.GetType() == typeof(Dictionary<string, object>))
{
foreach (KeyValuePair<string, object> item in kValue as Dictionary<string, object>)
{
XmlElement element = node.OwnerDocument.CreateElement(item.Key);
KeyValue2Xml(element, item);
node.AppendChild(element);
}
}
else if (kValue.GetType() == typeof(object[]))
{
object[] o = kValue as object[];
for (int i = 0; i < o.Length; i++)
{
XmlElement xitem = node.OwnerDocument.CreateElement("Item");
KeyValuePair<string, object> item = new KeyValuePair<string, object>("Item", o[i]);
KeyValue2Xml(xitem, item);
node.AppendChild(xitem);
}
}
else
{
XmlText text = node.OwnerDocument.CreateTextNode(kValue.ToString());
node.AppendChild(text);
}
}
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