Question

js中两个字符串时间如何判断大小？

Answer 1

最精确的比较方式应该是，知道字符串对应的时间的格式，然后将字符串转化成date型进行比较。

var time1 = new Date(d1.replace("-", "/").replace("-", "/"));

var time2 = new Date(d2.replace("-", "/").replace("-", "/"));

if(time1 > time2)alert("time1 大于 time2");

date1=new Date('12-11-2000'); 

date2=new Date('12-12-2000'); 

alert("日期差值为:"+(date2-date1));

var OneMonth = DateOne.substring(5,DateOne.lastIndexOf ("-"));

var OneDay = DateOne.substring(DateOne.length,DateOne.lastIndexOf ("-")+1);

var OneYear = DateOne.substring(0,DateOne.indexOf ("-"));

var TwoMonth = DateTwo.substring(5,DateTwo.lastIndexOf ("-"));

var TwoDay = DateTwo.substring(DateTwo.length,DateTwo.lastIndexOf ("-")+1);

var TwoYear = DateTwo.substring(0,DateTwo.indexOf ("-"));

(Date.parse(OneMonth+"/"+OneDay+"/"+OneYear) >

Date.parse(TwoMonth+"/"+TwoDay+"/"+TwoYear))