哪位大神帮忙解一下，要过程，尽量详细一些，谢谢了🙃
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=2∫[√(8-x²)-½x²]dx
=2∫√(8-x²)dx-2∫½x²dx
=2x√(8-x²)-2∫xd√(8-x²)-x³/3
=2x√(8-x²)-x³/3-∫d(8-x²)/√(8-x²)
=2x√(8-x²)-x³/3-[2(8-x²)³/² ]/3
=4√(8-4)-8/3-[2(8-4)³/² ]/3
-{0-0-[2(8-0²)³/² ]/3}
=8-8/3-16/3+32√2/3
=32√2/3
自己按此法再复算一遍
=2∫√(8-x²)dx-2∫½x²dx
=2x√(8-x²)-2∫xd√(8-x²)-x³/3
=2x√(8-x²)-x³/3-∫d(8-x²)/√(8-x²)
=2x√(8-x²)-x³/3-[2(8-x²)³/² ]/3
=4√(8-4)-8/3-[2(8-4)³/² ]/3
-{0-0-[2(8-0²)³/² ]/3}
=8-8/3-16/3+32√2/3
=32√2/3
自己按此法再复算一遍
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