二次根式
1个回答
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原式 = [(23-22)+(5/8-3/4)] + [999×(999+1)/(-5)^3 + (-5)^3·(-2)^3/(-5)^3] ×(-0.025)^2 - [(-5/4)^2×(-2)^3]×(1/3)
= [1-(1/8)] + [999×(-2)^3 + (-2)^3]×(0.025)^2 - (5/4)^2×(-2)^3×(1/3)
= [1-(1/8)] + (-2)^3×(999+1)×(1/40)^2 - (5/4)^2×(-2)^3×(1/3)
= [1-(1/8)] + (-2)^3×10×(1/4)^2 - 5^2×(1/4)^2×(-2)^3×(1/3)
= [1-(1/8)] + (-2)^3×(1/4)^2×[10-5^2×(1/3)]
= [1-(1/8)] + (-8)×(1/16)×(5/3)
= [1-(1/8)] + (-5/6)
= [1-(1/8)] + [(1/6)-1]
= -(1/8)+(1/6)
= 1/24
= [1-(1/8)] + [999×(-2)^3 + (-2)^3]×(0.025)^2 - (5/4)^2×(-2)^3×(1/3)
= [1-(1/8)] + (-2)^3×(999+1)×(1/40)^2 - (5/4)^2×(-2)^3×(1/3)
= [1-(1/8)] + (-2)^3×10×(1/4)^2 - 5^2×(1/4)^2×(-2)^3×(1/3)
= [1-(1/8)] + (-2)^3×(1/4)^2×[10-5^2×(1/3)]
= [1-(1/8)] + (-8)×(1/16)×(5/3)
= [1-(1/8)] + (-5/6)
= [1-(1/8)] + [(1/6)-1]
= -(1/8)+(1/6)
= 1/24
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