Question

求图中电流i

Answer 1

左边负载网络等效阻抗为 6||6||(4+4||4) = 2Ω
因此 i1 = 51V/(2Ω+15Ω) = 3A
因此 i = 1A + 1A/(4/(4+4)) = 1.5A

Answer 2

R=2
所以可得 i = 51/(2+15) = 3Ampere
i = 1 + 1/(4/(4+4)) = 1.5Ampere

Answer 3

R=17。 I=3。