Question

一道Java编程题目 求高手写下程序 谢谢了

三色球问题
若一个口袋中放有12个球，其中有3个红的，3个白的和6个黒的。问从中任取8个共有多少种不同的搭配？
【题目分析与算法设计】
设任取的红球个数为i，白球个数为j，则黒球个数为8-i-j。根据题意红球和白球个数的取值范围是0~3，在红球和白球个数确定的条件下，黒球个数取值应为8-i-j<=6。

Answer 1

一共13种组合

public class Ball {

public static void main(String[] args) {

int count = 0;

for(int red = 0; red <= 3; red++){
for(int white = 0; white <= 3; white++){
int black = 8 - red - white;
if(black <= 6){
count++;
System.out.println("(red, white, black): " + red + ", " + white + ", " + black);
}
}
}

System.out.println("Total " + count + " ways to get the ball!");
}
}

----------------
(red, white, black): 0, 2, 6
(red, white, black): 0, 3, 5
(red, white, black): 1, 1, 6
(red, white, black): 1, 2, 5
(red, white, black): 1, 3, 4
(red, white, black): 2, 0, 6
(red, white, black): 2, 1, 5
(red, white, black): 2, 2, 4
(red, white, black): 2, 3, 3
(red, white, black): 3, 0, 5
(red, white, black): 3, 1, 4
(red, white, black): 3, 2, 3
(red, white, black): 3, 3, 2
Total 13 ways to get the ball!