Question

C语言编程求1+1／2+1／3+1／4＋1／5……（用函数调用）

这2个答案都有错啊……能来个通过编译的么

Answer 1

#include<stdio.h>
float sum(float a,int b)
{b++;
a+=a/b;
return(a);
}
void main()
{int n,m,i,j;
float q;
n=1;m=1;q=0;
scanf("%d",&j);
for(i=1;i<j;i++)
q+=sum(n,m);
printf("%1.6f",q);
}

Answer 2

#include<stdio.h>
void main()
{
int n;
float Sum_daoshu(int n);
printf("请输入一个正整数: \n");
scanf("%d",&n);
printf("Result: %f\n",Sum_daoshu(n));
}

float Sum_daoshu(int n)
{
float Sum = 0;
for( int i = 1; i <= n; i++ )
{
Sum = Sum+((float)1)/i;
}
return Sum;
}

Answer 3

#include <iostream>
using namespace std;

double fx(int n)
{
return 1.0/n;
}

int main(void)
{
int n; cout<<"输入n的值"<<endl;
cin>>n;n++;
double sum=1.0;
while(n-- && n>=1)
{
sum+=fx(n);
}
cout<<sum<<endl;
return 0;
}

Answer 4

float Sum(int n)
{
float fSum = 0;
for( int i = 1; i < n+1; i++ )
{
fSum += ((float)1)/i;
}
return fSum;
}

void main()
{
int iMax;

printf("Input Max Number: ");
scanf("%d",&iMax);
printf("Result: %f",Sum(iMax));
}