八年级下分式数学题
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解：原式=[（x-y）/（x-y）^2 - y(x+y)/(x-y)(x-y) ] * xy/(y-1)
=[1/(x-y) - y/(x-y) ]*xy/(y-1)
=(1-y)/(x-y) * xy/(y-1)
=-(y-1)/(x-y) * xy/(y-1)
=-xy/(x-y)
=[1/(x-y) - y/(x-y) ]*xy/(y-1)
=(1-y)/(x-y) * xy/(y-1)
=-(y-1)/(x-y) * xy/(y-1)
=-xy/(x-y)
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