Question

【数学函数问题】已知:f(x)=sin[π/3(x+1)]-根号3cos[π/3(x+1)]，则f(1)+f(2)+f(3)+……+f(2009)等于?

哪位高手帮帮我吧.不会写..写出解题过程。。

Answer 1

f(x)=2(sin[π/3(x+1)]/2-√3/2cos[π/3(x+1)])=2(sin[π/3(x+1)]cosπ/3-sinπ/3cos[π/3(x+1)])
=2sin(π/3x)
f(1)+f(2)+f(3)+f(4)+f(5)+f(6)=0
f(1)+f(2)+f(3)+f(4)+f(5)......+f(2009)=f(1)+f(2)+f(3)+f(4)+f(5)=0

Answer 2

答案:
f(x)=2(sin[π/3(x+1)]/2-√3/2cos[π/3(x+1)])=2(sin[π/3(x+1)]cosπ/3-sinπ/3cos[π/3(x+1)])
=2sin(π/3x)
f(1)+f(2)+f(3)+f(4)+f(5)+f(6)=0

f(1)+f(2)+f(3)+f(4)+f(5)......+f(2009)=f(1)+f(2)+f(3)+f(4)+f(5)=0

Answer 3

这不周期函数么么么.......
详细一点，（x+1）在分母还是分子上

Answer 4

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Answer 5

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