因式分解方法x2－xy＋2x－y－3是x方-xy+2x-y-3,求解，谢谢
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x²-xy+2x-y-3
=x(x-y)+(x-y)+x-3
=(x-1)(x-y)+x-3
=(x-1)(x-y-1)-2
x²-xy+2x+y-3
=x(x-y)-(x-y)+3(x-1)
=(x-1)(x-y)+3(x-1)
=(x-1)(x-y+3)
=x(x-y)+(x-y)+x-3
=(x-1)(x-y)+x-3
=(x-1)(x-y-1)-2
x²-xy+2x+y-3
=x(x-y)-(x-y)+3(x-1)
=(x-1)(x-y)+3(x-1)
=(x-1)(x-y+3)
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