Question

分式计算一道题，加急！

(2x-1)/(x+1)+(3x+1)/(x+2)-(5x-11)/(x-1)
要过程

Answer 1

=(2x+2-3)/(x+1)+(3x+6-5)/(x+2)-(5x-5-6)/(x-1)
=[2(x+1)-3]/(x+1)+[3(x+2)-5]/(x+2)-[5(x-1)-6]/(x-1)
=2-3/(x+1)+3-5/(x+2)-5+6/(x-1)
=-3/(x+1)-5/(x+2)+6/(x-1)
=-( 2x^2-15x-23)/(x^3+2x^2-x-2)
多攒的分，好过年哦。

Answer 2

={2（x+1)-3}/(x+1)+{3(x+2)-5}/(x+2)-{5(x-1)-6}/(x-1)
=2-3/(x+1)+(3-5/(x+2))-(5+6/(x+1))
=(-2x^2+15x+23)/(x^3+2x^2-x-2)

Answer 3

解：(2x-1)/(x+1)+(3x+1)/(x+2)-(5x-11)/(x-1)
=[(2x-1)(x+2)+(3x+1)(x+1)]/(x+1)(x+2)-(5x-11)/(x-1)
=(5x^2+7x-1)/(x^2+3x+2)-(5x-11)/(x-1)
=[(5x^2+7x-1)(x-1)-(5x-11)((x^2+3x+2)]/(x^2+3x+2)(x-1)
=( - 2x^2+15x+23)/(x^3+2x^2-x-2)
正确答案如上，欢迎采纳！感谢

Answer 4

解：(2x-1)/(x+1)+(3x+1)/(x+2)-(5x-11)/(x-1)
=[(2x-1)(x+2)+(3x+1)(x+1)]/(x+1)(x+2)-(5x-11)/(x-1)
=(5x^2+7x-1)/(x^2+3x+2)-(5x-11)/(x-1)
=[(5x^2+7x-1)(x-1)-(5x-11)((x^2+3x+2)]/(x^2+3x+2)(x-1)
=( - 2x^2+15x+23)/(x^3+2x^2-x-2)