若x+y分之xy=2，则-x+3xy-y分之3x-xy+3y=多少？？？
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即x+y=xy/2
原式=[3(x-y)-xy]/[3xy-(x+y)]
=[3(xy/2)-xy]/[3xy-(xy/2)]
=(xy/2)/(5xy/2)
=1/5
原式=[3(x-y)-xy]/[3xy-(x+y)]
=[3(xy/2)-xy]/[3xy-(xy/2)]
=(xy/2)/(5xy/2)
=1/5
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