Question

求S=1+1/3+1/5+1/7+...1/(2n+1) C语言用写

Answer 1

#include<stdio.h>

int main()
{
float s = 1;
int n;
float i;

printf("请输入一个整数:n\n");
scanf("%d",&n);

for(i = 3; i <= 2*n+1; i +=2)
{
s = s + 1/i;
}
printf("s = %f\n",s);

return 0;
}

Answer 2

#include<iostream.h>
#include<stdlib.h>
void main()
{
int n,i;
double sum=0;
cout<<"�0�5�0�5�0�8�0�1�0�6�0�5n:"<<endl;
cin>>n;
if(n<0)
{
cout<<"wrong data!"<<endl;
exit(0);
}
cout<<"s=";
for(i=0;i<=n;i++)
{
sum+=(double)1/(2*i+1);
if(i==0) cout<<1;
else
cout<<"+1/"<<2*i+1;
}
if(n==0) exit(1);
cout<<"="<<sum<<endl;
}

Answer 3

void main()
{
float s=1;
for(int n=0;n<100;n++)
{
s+=1/(2*n)+1;
}
printf("n=100的结果是：%f",s);
}