详细步骤 谢谢
2014-08-08
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若a>0,b>0,a+b=1,则1/a>1,1/b>1
1=a+b≥2ab^(1/2)
ab^(1/2)≤1/2
ab≤1/4
1/ab≥4 当a=b=1/2取等号
(1/a^2-1)(1/b^2-1)=(1/a+1)(1/a-1)(1/b+1)(1/b-1)
=(1/a+1)(1/b+1)(1/a-1)(1/b-1)
=(1/ab+1/a+1/b+1)(1/ab-1/a-1/b+1)
=(1/ab+(a+b)/ab+1)(1/ab-(a+b)/ab+1)
=2/ab+1≥2*4+1=9
当a=b=1/2
(1/a^2-1)(1/b^2-1)的最小值是为9
1=a+b≥2ab^(1/2)
ab^(1/2)≤1/2
ab≤1/4
1/ab≥4 当a=b=1/2取等号
(1/a^2-1)(1/b^2-1)=(1/a+1)(1/a-1)(1/b+1)(1/b-1)
=(1/a+1)(1/b+1)(1/a-1)(1/b-1)
=(1/ab+1/a+1/b+1)(1/ab-1/a-1/b+1)
=(1/ab+(a+b)/ab+1)(1/ab-(a+b)/ab+1)
=2/ab+1≥2*4+1=9
当a=b=1/2
(1/a^2-1)(1/b^2-1)的最小值是为9
追答
解:设x=lg2,y=lg5,则x+y=lg2+lg5=lg10=1
原式=x^3+y^3+3xy
=(x+y)(x^2-xy+y^2)+3xy
=x^2-xy+y^2+3xy
=x^2+2xy+y^2
=(x+y)^2
=1
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