Question

已知集合A={x²-3x-10≤0},B={x|m+1≤x≤2m-1}，（1）当m=3时，求集合A∩B，A∪B

（2）若B⊆A，求实数m的取值范围

Answer 1

(1) x^2-3x-10<=0
(x+2)(x-5)<=0
A={x|-2=<x<=5}
m=3
m+1<=x<=2m-1
B={x|4<=x<=5}
A∩B={x|4=<x<=5}
AUB={x|-2=<x<=5}
(2) B⊆A

m+1>=-2
m>=-3
2m-1<=5
m<=3
m的取值范围：-3=<m<=3