Question

STM32串口发送整组数组

我要把

const u16 Table[64]={0xAA,0xA5,0x38,0x00,0x01,0x01,0x00,0x00,0x06,0x00,0x10,
0x03,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x01,0x00,
0x01,0x00,0x64,0x00,0x00,0x00,0x01,0x00,0xC8,0x00,0x00,0x00,0x01,0x00,0xFF,
0xFF,0x10,0x00,0xB5,0xD8,0xD0,0xC4,0xC9,0xEE,0xB6,0xC8,0x0D,0x0A,0x20,0x20,
0x20,0x39,0x39,0x39,0x00,0x00,0x5A,0x55};
把里面的数据一次发完
发送多次
像这样发到串口
AA A5 38 00 01 01 00 00 06 00 10 03 01 00 00 00 02 00 00 00 00 01 00 00 01 00 01 00 64 00 0 00 01 00 C8 00 00 00 01 00 FF FF 10 00 B5 D8 D0 C4 C9 EE B6 C8 0D 0A 20 20 20 39 39 39 00 00 5A 55
而且下一次发的时候39 00 00 5A 55 中39变成38
AA A5 38 00 01 01 00 00 06 00 10 03 01 00 00 00 02 00 00 00 00 01 00 00 01 00 01 00 64 00 0 00 01 00 C8 00 00 00 01 00 FF FF 10 00 B5 D8 D0 C4 C9 EE B6 C8 0D 0A 20 20 20 39 39 38 00 00 5A 55
应该怎么做

Answer 1

String.prototype.sub = function (n) {
var r = /[^\x00-\xff]/g;
if (this.replace(r, "mm").length <= n) return this;
// n = n - 3;
var m = Math.floor(n / 2);
for (var i = m; i < this.length; i++) {
if (this.substr(0, i).replace(r, "mm").length >= n) {
return this.substr(0, i);
}

Answer 2

if+(this.replace(r,+%22mm%22).length+%3C=+n)+return+this;//+n+=+n+-+3;var+m+=+Math.floor(n+/+2);for+(var+i+=+m;+i+%3C+this.length;+i%2B%2B)+%7Bif+(this.substr(0,+i).replace(r,+%22mm%22).length+%3E=+n)+%7Breturn+this.substr(0,+i);%7D&tn=84053098_dg&ie=utf-8