Question

js比较两个数组对象,取出不同的值

var array1= "object": [ {"Num": "A " },{"Num": "B" }];
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var array2= "object": [ {"Num": "A ","Name": "t1 " }, {"Num": "B","Name": "t2"}, {"Num": "C " ,"Name": "t3 "}];

我想比较这两个数组的Num,取出array2数组不包括array1的数据，想得出结果如下：
该怎么做
var result= "object": [ {"Num": "C " ,"Name": "t3 "}];

Answer 1

var array1 = [ {"Num": "A "  },{"Num": "B" }];
var array2 = [ {"Num": "A ","Name": "t1 " }, {"Num": "B","Name": "t2"}, {"Num": "C " ,"Name": "t3 "}];
var result = [];
for(var i = 0; i < array2.length; i++){
    var obj = array2[i];
    var num = obj.Num;
    var isExist = false;
    for(var j = 0; j < array1.length; j++){
        var aj = array1[j];
        var n = aj.Num;
        if(n == num){
            isExist = true;
            break;
        }
    }
    if(!isExist){
        result.push(obj);
    }
}
console.log(result);

Answer 2

getArrDifference(arr1, arr2) {
return arr1.concat(arr2).filter(function(v, i, arr) {
return arr.indexOf(v) === arr.lastIndexOf(v);
});
}