![](https://iknow-base.cdn.bcebos.com/lxb/notice.png)
1个回答
展开全部
一阶非齐次线性微分方程y'+p(x)y=q(x),通解为:
=e^[-∫p(x)dx](c+∫q(x)e^[∫p(x)dx]dx]
带入p,q得
x=e^[-∫-2/ydy](c+∫5e^[∫-2/ydy]dy]
=e^[lny^2](c+∫5e^[-lny^2]dy]
=y^2(c+∫5/y^2dy]
=y^2(c-5/y)
=cy^2-5y
=e^[-∫p(x)dx](c+∫q(x)e^[∫p(x)dx]dx]
带入p,q得
x=e^[-∫-2/ydy](c+∫5e^[∫-2/ydy]dy]
=e^[lny^2](c+∫5e^[-lny^2]dy]
=y^2(c+∫5/y^2dy]
=y^2(c-5/y)
=cy^2-5y
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询