展开全部
(4)
lim((x,y)->(0,0)) xy/[√(2-e^(xy)) -1 ]
=lim((x,y)->(0,0)) xy.[√(2-e^(xy)) +1 ]/ [ 1 - e^(xy) ]
=lim((x,y)->(0,0)) xy.[√(2-e^(xy)) +1 ]/ (-xy)
=lim((x,y)->(0,0)) -[√(2-e^(xy)) +1 ]
= -(1+1)
=-2
(5)
lim((x,y)->(2,0)) sin(xy)/y
=lim((x,y)->(2,0)) xy/y
=lim((x,y)->(2,0)) x
=2
(6)
lim((x,y)->(0,0)) [ 1- cos(x^2+y^2) ]/[ (x^2+y^2).e^(x^2.y^2) ]
=lim((x,y)->(0,0)) (1/2)(x^2+y^2)^2 /[ (x^2+y^2).e^(x^2.y^2) ]
=lim((x,y)->(0,0)) (1/2)(x^2+y^2) /e^(x^2.y^2)
=0
lim((x,y)->(0,0)) xy/[√(2-e^(xy)) -1 ]
=lim((x,y)->(0,0)) xy.[√(2-e^(xy)) +1 ]/ [ 1 - e^(xy) ]
=lim((x,y)->(0,0)) xy.[√(2-e^(xy)) +1 ]/ (-xy)
=lim((x,y)->(0,0)) -[√(2-e^(xy)) +1 ]
= -(1+1)
=-2
(5)
lim((x,y)->(2,0)) sin(xy)/y
=lim((x,y)->(2,0)) xy/y
=lim((x,y)->(2,0)) x
=2
(6)
lim((x,y)->(0,0)) [ 1- cos(x^2+y^2) ]/[ (x^2+y^2).e^(x^2.y^2) ]
=lim((x,y)->(0,0)) (1/2)(x^2+y^2)^2 /[ (x^2+y^2).e^(x^2.y^2) ]
=lim((x,y)->(0,0)) (1/2)(x^2+y^2) /e^(x^2.y^2)
=0
更多追问追答
追问
4小问为什么分母直接就变成xy了
追答
(x,y)->(0,0)
e^(xy) ~ 1+xy
1- e^(xy) ~ -xy
(4)
lim((x,y)->(0,0)) xy/[√(2-e^(xy)) -1 ]
=lim((x,y)->(0,0)) xy.[√(2-e^(xy)) +1 ]/ [ 1 - e^(xy) ]
=lim((x,y)->(0,0)) xy.[√(2-e^(xy)) +1 ]/ (-xy)
=lim((x,y)->(0,0)) -[√(2-e^(xy)) +1 ]
= -(1+1)
=-2
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询