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(2)
f(1+x)= af(x)
f'(0) =b
---------
f'(1)
=lim(h->0) [f(1+h) - f(1)] / h
=lim(h->0) [af(h) - f(1)] / h
=lim(h->0) [af(h) - f(1+0)] / h
=lim(h->0) [af(h) - af(0)] / h
=alim(h->0) [f(h) - f(0)] / h
=af'(0)
=ab
f(1+x)= af(x)
f'(0) =b
---------
f'(1)
=lim(h->0) [f(1+h) - f(1)] / h
=lim(h->0) [af(h) - f(1)] / h
=lim(h->0) [af(h) - f(1+0)] / h
=lim(h->0) [af(h) - af(0)] / h
=alim(h->0) [f(h) - f(0)] / h
=af'(0)
=ab
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