Question

求这道题的解法

求这道题的解法求解这道题的答案

Answer 1

Answer 2

sin(xy)-cos(x-y)=0 cos(xy)·(xy)'+sin(x-y)·(x-y)'=0 cos(xy)·(y+xy')+sin(x-y)·(1-y')=0 [sin(x-y)-xcos(xy)]·y'=sin(x-y)+ycos(xy) y'=[sin(x-y)+ycos(xy)]/[sin(x-y)-xcos(xy)] dy/dx=[sin(x-y)+ycos(xy)]/[sin(x-y)-xcos(xy)]