Question

像这种题怎么解，完全不会平方差公式

每次遇到都不会，化简步骤详细一点，最好公式也列出来，太笨了老是学不会，跪求学霸

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Answer 1

还有

追答

Answer 2

(x³+3x²+2x)/(x²-x-6)
=[x·(x²+3x+2)]/(x+2)(x-3)
=[x·(x+1)·(x+2)]/(x+2)(x-3)
=x(x+1)/(x-3)
(x²-2x+1)/(x³-x)
=(x-1)²/[x·(x²-1)]
=(x-1)²/[x·(x+1)·(x-1)]
=(x-1)/[x·(x+1)]