分解因式;X²-6X+9-Y² (a²+b²-1)²-4a²b²
2个回答
2011-01-30
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X²-6X+9-Y²
=(x-3)^2-y^2
=(x-3+y)(x-3-y)
(a²+b²-1)²-4a²b²
=(a^2+b^2+2ab-1)(a^2+b^2-2ab-1)
=[(a+b)^2-1)][(a-b)^2-1]
=(a+b+1)(a+b-1)(a-b+1)(a-b-1)
=(x-3)^2-y^2
=(x-3+y)(x-3-y)
(a²+b²-1)²-4a²b²
=(a^2+b^2+2ab-1)(a^2+b^2-2ab-1)
=[(a+b)^2-1)][(a-b)^2-1]
=(a+b+1)(a+b-1)(a-b+1)(a-b-1)
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