x²-4x+4/x²-1÷(3/x+1 -1),其中x=-2
2个回答
展开全部
(x²-4x+4)/(x²-1)÷(3/(x+1)
-1)
=(x-2)²/[(x+1)(x-1)]÷(2-x)/(x+1)
=-(x-2)²/[(x+1)(x-1)]·(x+1)/(x-2)
=-(x-2)/(x-1)
当x=-2时
原式=-(-2-2)/(-2-1)
=-4/3
-1)
=(x-2)²/[(x+1)(x-1)]÷(2-x)/(x+1)
=-(x-2)²/[(x+1)(x-1)]·(x+1)/(x-2)
=-(x-2)/(x-1)
当x=-2时
原式=-(-2-2)/(-2-1)
=-4/3
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展开全部
((-2+1)²((x+1)²(x-1))
当x=-2时
原式=-(-2-2)/(x-2))
=-(x-2)//(2-x))=-(x-2)²(((x+1)(x-1))÷((2-x)/((x²(x+1)
-1))
=(x-2)²((x+1)(x-1)·(x+1)/(x+1)))
=(x-2)²/((x+1)(x-1)·(x+1)/-1)÷(3/-4x+4)//-3=-4/(((x+1)(x-1))÷((3-x-1)//(-2-1))
=4/(x+1)))
=(x-2)²(x²
当x=-2时
原式=-(-2-2)/(x-2))
=-(x-2)//(2-x))=-(x-2)²(((x+1)(x-1))÷((2-x)/((x²(x+1)
-1))
=(x-2)²((x+1)(x-1)·(x+1)/(x+1)))
=(x-2)²/((x+1)(x-1)·(x+1)/-1)÷(3/-4x+4)//-3=-4/(((x+1)(x-1))÷((3-x-1)//(-2-1))
=4/(x+1)))
=(x-2)²(x²
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