sin15°+cos15°的值等于 ___ .?
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解题思路:把原式提取 2 ,然后利用特殊角的三角函数值及两角和的正弦函数公式化简可得值.
sin15°+cos15°=
2(
2
2sin15°+
2
2cos15°)=
2(sin15°cos45°+cos15°sin45°)
=
2sin(15°+45°)=
2sin60°=
2×
3
2=
6
2.
故答案为:
6
2
,4,sin15+cos15=genhao2(sin15cos45+cos15sin45)=genhao2sin60=genhao2sin60,1,(sin15+cos15)^2=1+sin30=3/2
sin15+cos15=根号6/2
(因为sin15°+cos15°>0),1,sin15°+cos15°
=√2sin(15°+45°)
=√2sin60°
=√6/2,0,sin15°+cos15°
=√2*(√2/2sin15°+√2/2*cos15°)
=√2*(sin15°cos45°+cos15°sin45°)
=√2*sin(15°+45°)
=√2*sin60°
=√2*√3/2
=√6/2,0,
sin15°+cos15°=
2(
2
2sin15°+
2
2cos15°)=
2(sin15°cos45°+cos15°sin45°)
=
2sin(15°+45°)=
2sin60°=
2×
3
2=
6
2.
故答案为:
6
2
,4,sin15+cos15=genhao2(sin15cos45+cos15sin45)=genhao2sin60=genhao2sin60,1,(sin15+cos15)^2=1+sin30=3/2
sin15+cos15=根号6/2
(因为sin15°+cos15°>0),1,sin15°+cos15°
=√2sin(15°+45°)
=√2sin60°
=√6/2,0,sin15°+cos15°
=√2*(√2/2sin15°+√2/2*cos15°)
=√2*(sin15°cos45°+cos15°sin45°)
=√2*sin(15°+45°)
=√2*sin60°
=√2*√3/2
=√6/2,0,
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