用十字相乘法分解因式:(1)x^2+y^2-2xy-10x+10y+16=?(2)2x^2+3xy-2y^2-x+8y-?
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3,1·(x-y)^2-10(x-y)+16=(x-y-8)(x-y-2)
2`(x+2y)(2x-y)-(x-8y)-6=(x+2y-2)(2x-y+3),2,x^2+y^2-2xy-10x+10y+16=(x-y)^2-10(x-y)+16
=(x-y-8)(x-y-2)
2x^2+3xy-2y^2-x+8y-6=(2x-y)(x+2y)-(x-8y)-6
=(x+2y-2)(2x-y+3),2,1·(x-y)^2-10(x-y)+16=(x-y-8)(x-y-2)
2`(x+2y)(2x-y)-(x-8y)-6=(x+2y-2)(2x-y+3),1,用十字相乘法分解因式:(1)x^2+y^2-2xy-10x+10y+16=?(2)2x^2+3xy-2y^2-x+8y-6=?
2`(x+2y)(2x-y)-(x-8y)-6=(x+2y-2)(2x-y+3),2,x^2+y^2-2xy-10x+10y+16=(x-y)^2-10(x-y)+16
=(x-y-8)(x-y-2)
2x^2+3xy-2y^2-x+8y-6=(2x-y)(x+2y)-(x-8y)-6
=(x+2y-2)(2x-y+3),2,1·(x-y)^2-10(x-y)+16=(x-y-8)(x-y-2)
2`(x+2y)(2x-y)-(x-8y)-6=(x+2y-2)(2x-y+3),1,用十字相乘法分解因式:(1)x^2+y^2-2xy-10x+10y+16=?(2)2x^2+3xy-2y^2-x+8y-6=?
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