Question

因式分解(a+2b)^2-a^2-2ab

还有
-2(m-n)^2+32

x(x-5)^2+x(x-5)(x+5)

Answer 1

(a+2b)^2-a^2-2ab
=a^2+4ab+b^2-a^2-2ab
=2ab+b^2
=b(2a+b)

-2(m-n)^2+32
=2{16-(m-n)^2}
=2(4+m-n)(4-m+n)

x(x-5)^2+x(x-5)(x+5)
=x(x-5)(x-5+x+5)
=2x^2(x-5)

Answer 2

原式=a^2+4ab+4b^2-a^2-2ab=2ab+4b^2=2b(a+2b)

Answer 3

=a^2+4ab+4b^2-a^2-2ab=4b^2+2ab=2b(a+2b)