Question

先化简，再求值：(x^2+5x+6)/(x+3)÷(x^2-4)/(x-3)-1,其中x=根号3

先化简，再求值：(x^2+5x+6)/(x+3)÷(x^2-4)/(x-3)-1,其中x=根号3

Answer 1

先化简，再求值：(x²+5x+6)/(x+3)÷(x²-4)/(x-3)-1,其中x=√3
解：原式＝[(x+2)(x+3)/(x+3)]×[(x-3)/(x-2)(x+2)]-1
=(x-3)/(x-2)-1=[(x-3)-(x-2)]/(x-2)=-1/(x-2)=-/(√3-2)=(√3)+2

Answer 2

（x+2)(x+3) (x+2)(x-2) （x+2)(x+3) (x-3) (x-3)
-----------------÷--------------- -1= ------------------ X --------------- =---------
(x+3) (x-3) (x+3) (x+2)(x-2) (x-2)

因为x=根号3
所以原式=根号三-3
---------------
跟好3-2

Answer 3

题不太清楚
原式=(x+2)(x+3)/(x+3)÷(x+2)(x-2)/(x-4)
=(x+2)÷(x+2)(x-2)/(x-4)
=(x-4)/(x+2)
将x=根号3代入，得(根号3-4)/ (根号3+2）

Answer 4

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