Question

求以下方程的解

3/2（x+1）-2/3（3x-6）=-1/10
4(15-2x)-6x=16x-6(8-x)
16(1-2x)-4(11-2x)=7
16(1-2x)-4(11-2x)=7(2-6x)
6[(32+1)/3+(x/6)]=4[(3x+2)/4-7/4]
3/4[(4/3)x-(2/3)x+4]=2x
1/2[x/3-1/2((3/2)x-1)]=x/12
2/3[3/2(1/4x-1/2)-3]+2=x
2{2[2(2x+1)+1]+1}+1=-1
我会做问题是题量太多了，我还有4篇作文20+的应用题+整本英语书的词 短语

Answer 1

1. 3/2（x+1）-2/3（3x-6）=-1/10
(3/2)x+(3/2)-2x+4=-(1/10)
-(1/2)x+(11/2)=-(1/10)
-(1/2)x=-(56/5)
x=(112/5)
2. 4(15-2x)-6x=16x-6(8-x)
60-8x-6x=16x-48+6x
60-14x=22x-48
36x=60+48
x=108/36=3
3. 16(1-2x)-4(11-2x)=7
16-32x-44+8x=7
-24x-28=7
-24x=35
x=-(35/24)
4. 16(1-2x)-4(11-2x)=7(2-6x)
16-32x-44+8x=14-42x
-24x-28==14-42x
18x=42
x=7/3
5. 6[(32+1)/3+(x/6)]=4[(3x+2)/4-7/4]
6x(32+1)/3+x=4(3x+2)/4-7
66+x=3x-5
2x=71
x=(71/2)
6. 3/4[(4/3)x-(2/3)x+4]=2x
(3/4)(4/3)x-(2/3)(3/4)x+3=2x
x-(1/2)x+3=2x
(1/2)x+3=2x
(3/2)x=3
x=2
7. 1/2{x/3-1/2[(3/2)x-1]}=x/12
(1/2)(x/3)-(1/2)(1/2)[(3/2)x-1]=x/12
(x/6)-(1/4)[(3/2)x-1]=x/12
(x/6)-(3/8)x+(1/4)=(x/12)
(1/6)x-(3/8)x+(1/4)=(x/12)
-(5/24)x+(1/4)=(1/12)x
(7/24)x=(1/4)
x=(6/7)
8. 2/3[3/2(1/4x-1/2)-3]+2=x
(2/3)(3/2)[(1/4)x-(1/2)]-2+2=x
(1/4)x-(1/2)=x
(3/4)x=-(1/2)
x=-(2/3)
9. 2{2[2(2x+1)+1]+1}+1=-1
2[2(4x+2+1)+1]+1=-1
2(8x+6+1)+1=-1
16x+14+1=-1
16x=-16
x=-1
不保证全对，不验算，不可以太依赖别人，自己验算吧！

Answer 2

这个……不是一元一次吗……带入消除就好了

Answer 3

1 x=56/5 2: x=3
3:x=-35/24 4:x=7/3
5:x=71/2
6:x =2
7:x=6/11
8: x=-2/3 9: x=-1

Answer 4

打开公因式