关于因式分解的题
1.(-a的5次方)X(-a²)³X(-a³)²=多少?2.若(x-2)²+(y+3)²=0,则(x+y)&s...
1.(-a的5次方)X(-a²)³X(-a³)²=多少?
2.若(x-2)²+(y+3)²=0,则(x+y)²=多少?
3.下列计算正确的是?A.2a+3b=5ab B.(-ab)²=a²b²
4.不论M,N为何有理数,m²+n²-2m-4n+8的值总是?A负数,B 0 C正数 D非负数
5.x(x-y)²-y(y-x)²可化为 A,(x-y)² B,(x-y)³ C,(y-x)²D,(y-x)³
6.计算题
(过程要有)1.[(xy²)²]³+[(-xy²)²]³
2.(-1/2a²b)(2/3b²-1/3a+1/4)
3.因式分解 25(a+b)²-16(a-b)² 展开
2.若(x-2)²+(y+3)²=0,则(x+y)²=多少?
3.下列计算正确的是?A.2a+3b=5ab B.(-ab)²=a²b²
4.不论M,N为何有理数,m²+n²-2m-4n+8的值总是?A负数,B 0 C正数 D非负数
5.x(x-y)²-y(y-x)²可化为 A,(x-y)² B,(x-y)³ C,(y-x)²D,(y-x)³
6.计算题
(过程要有)1.[(xy²)²]³+[(-xy²)²]³
2.(-1/2a²b)(2/3b²-1/3a+1/4)
3.因式分解 25(a+b)²-16(a-b)² 展开
展开全部
1.-a^5X(-a^6)Xa^6=a^17
2.若(x-2)²+(y+3)²=0,则(x+y)²=多少?
得出,x=2,y=-3,(x+y)²=(2-3)^2=1
3 B.(-ab)²=a²b²正确
4 m²+n²-2m-4n+8=(m-1)^2+(n-2)^2+3 总是正数
5x(x-y)²-y(y-x)²=x(x-y)²-y(x-y)²=(x-y)(x-y)²=(x-y)^3
6 1.[(xy²)²]³+[(-xy²)²]³=[(x^2y^4]³+[(x^2y^4]³=x^6y^12+x^6y^12=2x^6y^12
2.(-1/2a²b)(2/3b²-1/3a+1/4)
=-1/2a²bX2/3b²-(-1/2a²bX1/3a)+(-1/2a²bX1/4)
=-1/3a²b^3+1/6a^3b-1/8a²b
3.因式分解 25(a+b)²-16(a-b)² 平方差公式
=[5(a+b)+4(a-b)][5(a+b)-4(a-b)]
= [5a+5b+4a-4b][5a+5b-4a+4b]
=(9a+b)(a+9b)
2.若(x-2)²+(y+3)²=0,则(x+y)²=多少?
得出,x=2,y=-3,(x+y)²=(2-3)^2=1
3 B.(-ab)²=a²b²正确
4 m²+n²-2m-4n+8=(m-1)^2+(n-2)^2+3 总是正数
5x(x-y)²-y(y-x)²=x(x-y)²-y(x-y)²=(x-y)(x-y)²=(x-y)^3
6 1.[(xy²)²]³+[(-xy²)²]³=[(x^2y^4]³+[(x^2y^4]³=x^6y^12+x^6y^12=2x^6y^12
2.(-1/2a²b)(2/3b²-1/3a+1/4)
=-1/2a²bX2/3b²-(-1/2a²bX1/3a)+(-1/2a²bX1/4)
=-1/3a²b^3+1/6a^3b-1/8a²b
3.因式分解 25(a+b)²-16(a-b)² 平方差公式
=[5(a+b)+4(a-b)][5(a+b)-4(a-b)]
= [5a+5b+4a-4b][5a+5b-4a+4b]
=(9a+b)(a+9b)
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