Question

高数1的题目求导计算，为了补考，大家帮帮忙，分不多，表心意

Answer 1

简单

Answer 2

dx=2sintcostdt
对t求导得cos(t-y)=costcosy+sintsiny对t求导得-sintcosy-costsiny*dy/dt+costsiny+sintcosy*dy/dt
dy/dt*sint+y*cost+sintcosy+costsiny*dy/dt-costsiny-sintcosy*dy/dt=0
所以dy/dt=(costsiny-sintcosy-ycost)/(sint+costsiny-sintcosy)
所以dy=(costsiny-sintcosy-ycost)/(sint+costsiny-sintcosy)*dt
所以dy/dx就把dt消掉了
dy/dx=(costsiny-sintcosy-ycost)/[(sint+costsiny-sintcosy)*2sintcost]
答案这么麻烦我自己都怀疑有没有做错了你看下吧