Question

约分：x²-36/2x+12 a²-2a+1/1-a 3x-4y/8xy-6x²

约分：x²-36/2x+12 a²-2a+1/1-a 3x-4y/8xy-6x²

Answer 1

x^2-36/2x+12
=(x+6)(x-6)/2(x+6)
=1/2x-3

a2-2a+1/1-a
=(a+1)(a-1)/-(a+1)
=-(a-1)
=1-a
3x-4y/8xy-6x2
=(3x-4y)/-2x(3x-4y)
=1/2x

Answer 2

x²-36/2x+12
=(x+6)(x-6)/2(x+6)
=(x-6)/2

a²-2a+1/1-a
=(a-1)^2/(-(a-1))
=-(a-1)
=1-a

3x-4y/8xy-6x²
=(3x-4y)/[2x(4y-3x)]
=-1/(2x)