
已知函数f(x)=ax^2+bx+c,且|f(-1)|<=1,|f(0)|<=1,|f(1)|<=1.证明:当-1<=x<=1时,|f(x)|<=5/4
已知函数f(x)=ax^2+bx+c,且|f(-1)|<=1,|f(0)|<=1,|f(1)|<=1.证明:当-1<=x<=1时,|f(x)|<=5/4...
已知函数f(x)=ax^2+bx+c,且|f(-1)|<=1,|f(0)|<=1,|f(1)|<=1.证明:当-1<=x<=1时,|f(x)|<=5/4
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