已知A=—3ax ^2-AX+3，B=—ax-1/2ax-1
2个回答
展开全部
1/3A-B
=1/3*(-3ax^2-ax+3)-(-ax^2-1/2ax-1)
=-ax^2-1/3ax+1+ax^2+1/2ax+1
=1/6ax+2
当a=2，x=3时
1/6ax+2
=1/6*2*3+2
=1+2
=3
=1/3*(-3ax^2-ax+3)-(-ax^2-1/2ax-1)
=-ax^2-1/3ax+1+ax^2+1/2ax+1
=1/6ax+2
当a=2，x=3时
1/6ax+2
=1/6*2*3+2
=1+2
=3
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
1/3A-B
=1/3*(-3ax^2-ax+3)-(-ax^2-1/2ax-1)
=-ax^2-1/3ax+1+ax^2+1/2ax+1
=1/6ax+2
当a=2，x=3时
1/6ax+2
=1/6*2*3+2
=1+2
=3
=1/3*(-3ax^2-ax+3)-(-ax^2-1/2ax-1)
=-ax^2-1/3ax+1+ax^2+1/2ax+1
=1/6ax+2
当a=2，x=3时
1/6ax+2
=1/6*2*3+2
=1+2
=3
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
