求答案,谢谢了
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解:2AB²-C=2(2x²+3xy-y²)(-½xy)²-(1/8x³y³-1/4x²y^4)
=2(2x²+3xy-y²)(1/4x²y²)-(1/8x³y³-1/4x²y^4)
=2(1/2x^4+3/4x³y^4-1/4x²y^4)-(1/8x³y³-1/4x²y^4)
=2x^4+3/2x³y^4-1/2x²y^4-1/8x³y³+1/4x²y^4
=2x^4+3/2x³y^4-1/4x²y^4-1/8x³y³
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=2(2x²+3xy-y²)(1/4x²y²)-(1/8x³y³-1/4x²y^4)
=2(1/2x^4+3/4x³y^4-1/4x²y^4)-(1/8x³y³-1/4x²y^4)
=2x^4+3/2x³y^4-1/2x²y^4-1/8x³y³+1/4x²y^4
=2x^4+3/2x³y^4-1/4x²y^4-1/8x³y³
~亲,如果你认可我的回答,请点击【采纳为满意回答】按钮~~
手机提问的朋友在客户端上评价点【满意】即可。
~你的采纳是我前进的动力~~O(∩_∩)O,互相帮助,共同进步!
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