Question

1+1/3+3/5+5/7+(2N-1)/(2N+1)C++程序

Answer 1

#include<iostream>
using namespace::std;double sum (int n)
{
double s = 1; for(int i=2;i<=n;++i)
{
s+=(2*(i-1)-1.0)/(2*(i-1)+1);
}
return s;
}int main()
{
int item = 0;
cout<<"输入项数：";
cin>>item;
cout<<"输出结果求和："<<sum(item);
system("pause");
return 0;
}