Question

如何用java递归生成带children的json串啊？数据集已经有了在下面。

如题对应的字段如下，大侠帮帮忙啊 ！ (其中children是那些lft,rgt值中间的一些菜单，depth是该菜单的深度，code不用考虑)
------------------------------ id, menu_Name ,lft,rgt,m_code,depth
Depart dept1= new Depart(1, "ELECTRONICS", 1, 20, "code", 0); Depart dept2= new Depart(2, "TELEVISIONS", 2, 9, "code", 1); Depart dept3= new Depart(3, "TUBE", 3, 4, "code", 2); Depart dept4= new Depart(4, "LCD", 5, 6, "code", 2); Depart dept5= new Depart(5, "PLASMA", 7, 8, "code", 2); Depart dept6= new Depart(6, "PORTABLE ELECTRONICS", 10, 19, "code", 1); Depart dept7= new Depart(7, "MP3 PLAYERS", 11, 14, "code", 2); Depart dept8= new Depart(8, "FLASH", 12, 13, "code", 3); Depart dept9= new Depart(9, "CD PLAYERS", 15, 16, "code", 2); Depart dept10= new Depart(10, "2 WAY RADIOS", 17, 18, "code", 2);
{
"items": [
"children":[
{
"children": [
{
"children": [children。。。。。],//递归即可
}
"text": "TELEVISIONS"
}，
{
"children": [
{
"children": [children。。。。。],//递归即可
}
"text": "PORTABLE ELECTRONICS"
}]
],
text:'ELECTRONICS'
]
}
。。。。。略

Answer 1

不清楚你的业务需求。
1、数据存放在xml文件中，读取xml文件
2、json格式，如果你的数据有规律可循，可以用代码循环遍历
3、如果数据来自数据库，那么使用sql，一般的数据库都提供查询“树”的sql

Answer 2

使用simplejson这个开源项目包就行