Question

C语言问题 错误 noname.c 39: 符合指令缺少} 在main函数中

#include<stdio.h>
#define DIGITMAX 16
#define Total 28000
int *start;
void getsum(int sum,int row,int *p)
{
int i,k,temp,*ptm;
if(sum>Total)return;
for(i=row;i<DIGITMAX;i++)
{
temp=sum+*(start+i);
if(temp==Total)
{
*p=*(start+i);
*(p+1)=-1;
printf("\n-----------\n");
for(ptm=start,k=0;k<20;k++,ptm++){
if(*ptm==-1)break;
printf("%d ",*ptm);
}
}
if(temp>Total)return;
*p=*(start+i);
getsum(temp,i+1,p+1);
}
}
main()
{
int num[16]={20706.6,12962.37,4030,2913.73,6858.65,11400,1536,15807.25,
5246.81,7017.5,2389.38,4270,5708.5,17510.05,2703.8,19765.43};
int *p,sum;
start=num,p=start,sum=0;
printf("1.=%d",*start);
getsum(sum,0,p);
getche();
return 0;

Answer 1

你main函数少右括号

main()
{
    int num[16]={20706.6,12962.37,4030,2913.73,6858.65,11400,1536,15807.25,
                5246.81,7017.5,2389.38,4270,5708.5,17510.05,2703.8,19765.43};
    int *p,sum;
    start=num,p=start,sum=0;
    printf("1.=%d",*start);
    getsum(sum,0,p);
    getche();
    return 0;
}

Answer 2

最后一行，return 0; 下面少了个},　加上去就好了

追问

我主要是想在20706.6,12962.37,4030,2913.73,6858.65,11400,1536,15807.25,
5246.81,7017.5,2389.38,4270,5708.5,17510.05,2703.8,19765.43这些数字中，找出那么3或4或5个相加正好等于28000的，老兄能不能帮帮忙

追答

一个也没有