Question

一道英文数学题目，求解~

For two consecutive multiples of 4, the larger number is less than twice of the
smaller one by at least 16. Find the minimum values of the two numbers.

Answer 1

是这样的：
对于两个连续的4的倍数，大的数字比小的数字的2倍小至少16.求这两个数的最小值。
解：设小的数字为x，则大的数字为x+4
列不等式：2x-(x+4)≥16
所以得x≥20
所以这两个数字最小值为20,24

Answer 2

Horizontal: y = 9/2
Vertical: x = -5/2

When x approaches -5/2 from the left (x < -5/2), 9x - 3 < 0, 2x + 5 < 0, f(x) > 0 and approaches infinity. When x approaches -5/2 from the right (x > -5/2), 9x - 3 < 0, 2x + 5 > 0, f(x) < 0 and approaches negative infinity. So x = -5/2 is its vertical asymptote.

When x approaches infinity or negative infinity, the limit of f(x) is 9/2, which is its horizontal asymptote.
是否可以解决您的问题？