Question

php和ajax的json问题

echo " <tr class='hello'> ";
echo "<td>$bianhao </td> ";
echo " <td>$mingzhi</td>";
echo " <td>$fabushjian</td> ";
echo " <td>$shoujie</td> ";
echo " <td><input title='123' class='class' id={$bianhao} type='button' value='按钮'/></td>";
echo " <td>$jinge</td>";
echo " <td>$zhuanhao</td> ";
echo " <td>$renwu</td>";
echo " <td>$shuanlianjie</td>";
echo " <td>$yuancheng</td> ";
echo " <td>$ip</td>";
echo " <td>$dianshu</td> ";
echo " <td>$fabu</td>";
echo " <td>$beijie</td>";
echo " </tr>";
和一段文字，文字内容是“操作成功”，
ajax怎么把这些返回前台，文字是准备在前台一个提示，表格是数据库的一些内容，表格是想直接替换掉前台的表格的，怎么传回前台，表格里只是写了一点点，表格是FOR循环打印出来的，如果数据库里有100记录，不知道怎么写json

Answer 1

$.ajax({
type: "GET",
url: "xxxxx",//相对或者绝对地址
data: {},
dataType: "json",
success: function(data){
var html = '';
$.each(data, function(index, el){
html += " <tr class='hello'> " +"<td>"+ el.bianhao
+" </td>" ;
//后面需要的一直拼接
});
$('#resText').html(html);
}
});

上面是jquery的写法，把你读出来的数据，php端放在一个数组里面格式如
$data = [
['bianhao'=>1001,'mingzhi'=>'张三'],

]
echo json_encode($data);